What is the excess pressure inside a bubble of soap solution of radius 5.0 mm, given that the surface tension of soap solution is 2.5 × 10 -2 N/m. If an air bubble of the same dimension were formed at a depth of 40.0 cm inside a container containing the soap solution (of relative density 1.2) what would be pressure inside the bubble. [ 1 atm = 1.01 × 10 5 N/m 2 ]
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(20 N/m 2 , 1.05714 × 10 5 N/m 2 )
Sol. p excess = 
= 
= 20 N/m 2
p = p atm + h ρ g + = 1.01 × 10 5 + .40 × 1.2 × 10 3 × 9.8 + 
= 1.05714 × 10 5 N/m 2
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